4x^2-60x-504=0

Solution for 4x^2-60x-504=0 equation:

4x^2-60x-504=0

a = 4; b = -60; c = -504;
Δ = b2-4ac
Δ = -602-4·4·(-504)
Δ = 11664
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{11664}=108$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-108}{2*4}=\frac{-48}{8}
=-6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+108}{2*4}=\frac{168}{8}
=21
$